Let's see how much of this I can pull from memory LOL
0°C would be 32°F due to the fact that the 0 point in C is where water freezes, and 32 is where water freezes in F. Also 100°C is 212°F as water boils at each of these two points. Because I am bored, I'll try to work out some problems without screwing it up LOL.
The formula we always got was
Degrees Celcius = 5/9 (degrees Farinheight - 32)
So let's take the temperature 67 in F.
So we want DC, so I'll make that X
X = 5/9 (67-32)
X = 5/9 (35)
Then you can do it a few different ways, I did :
5 x 35 / 9 = 19.44, and that is rounded down to 19. lol
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Now from C to F. Let's take 30°C
30 = 5/9 (x - 32)
The way I figured to do this was
(30 x 9) / 5 + 32.
so we get
270 / 5 + 32.
54 + 32 = 86
... and I actually checked my work on a conversion chart and I was right :twisted: ... I really pulled that formula out of the air, but hey it works *shrug*.
Hope that helps.
-Brian
