Whats the temp where you are?

[B]

Let's see how much of this I can pull from memory LOL

0°C would be 32°F due to the fact that the 0 point in C is where water freezes, and 32 is where water freezes in F. Also 100°C is 212°F as water boils at each of these two points. Because I am bored, I'll try to work out some problems without screwing it up LOL.

The formula we always got was

Degrees Celcius = 5/9 (degrees Farinheight - 32)

So let's take the temperature 67 in F.

So we want DC, so I'll make that X

X = 5/9 (67-32)

X = 5/9 (35)

Then you can do it a few different ways, I did :

5 x 35 / 9 = 19.44, and that is rounded down to 19. lol

-----

Now from C to F. Let's take 30°C

30 = 5/9 (x - 32)

The way I figured to do this was

(30 x 9) / 5 + 32.

so we get

270 / 5 + 32.

54 + 32 = 86

... and I actually checked my work on a conversion chart and I was right :twisted:  ... I really pulled that formula out of the air, but hey it works *shrug*.

Hope that helps.

-Brian

[vive-la-france]

thanks for the formula  

Do you know that 0°C = 273° K   (K= Kelvin)

so for °K your formula becomes

°C + 273 = 5/9 (°F-32)   with °C+273 = °K  

wicked  no ? 8O

[Tiger Baby]

Let's see how much of this I can pull from memory LOL

0°C would be 32°F due to the fact that the 0 point in C is where water freezes, and 32 is where water freezes in F. Also 100°C is 212°F as water boils at each of these two points. Because I am bored, I'll try to work out some problems without screwing it up LOL.

The formula we always got was

Degrees Celcius = 5/9 (degrees Farinheight - 32)

So let's take the temperature 67 in F.

So we want DC, so I'll make that X

X = 5/9 (67-32)

X = 5/9 (35)

Then you can do it a few different ways, I did :

5 x 35 / 9 = 19.44, and that is rounded down to 19. lol

-----

Now from C to F. Let's take 30°C

30 = 5/9 (x - 32)

The way I figured to do this was

(30 x 9) / 5 + 32.

so we get

270 / 5 + 32.

54 + 32 = 86

... and I actually checked my work on a conversion chart and I was right :twisted:  ... I really pulled that formula out of the air, but hey it works *shrug*.

Hope that helps.

-Brian

*stares and drools* I got lost after you said "Lets see how much I can pull from memory"

[topher8467]

thanks for the formula  

Do you know that 0°C = 273° K   (K= Kelvin)

so for °K your formula becomes

°C + 273 = 5/9 (°F-32)   with °C+273 = °K  

wicked  no ? 8O

Okay; I'm confused ... The first train was leaving from where and going how fast?

[Tiger Baby]

I was lost a loooooong time ago!

[badsrx7]

thanks for the formula  

Do you know that 0°C = 273° K   (K= Kelvin)

so for °K your formula becomes

°C + 273 = 5/9 (°F-32)   with °C+273 = °K  

wicked  no ? 8O

Okay; I'm confused ... The first train was leaving from where and going how fast?

that makes me think of an episode of doug

[Tiger Baby]

thanks for the formula  

Do you know that 0°C = 273° K   (K= Kelvin)

so for °K your formula becomes

°C + 273 = 5/9 (°F-32)   with °C+273 = °K  

wicked  no ? 8O

Okay; I'm confused ... The first train was leaving from where and going how fast?

that makes me think of an episode of doug

I love that show!!

[vive-la-france]

lol @ Topher

i was talking about temperature : in Science we use Kelvin

[Tiger Baby]

Its 90 degrees outside. Andrea go swimming!

[topher8467]

lol @ Topher

i was talking about temperature : in Science we use Kelvin

I'm well aware that kelvins have to do with temperature.